Optimal. Leaf size=160 \[ -\frac {2 \sqrt {2} a^3 e^{3/2} \tanh ^{-1}\left (\frac {\sqrt {e} \cot (c+d x)+\sqrt {e}}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{d}-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {4 a^3 (e \cot (c+d x))^{3/2}}{3 d}+\frac {4 a^3 e \sqrt {e \cot (c+d x)}}{d}-\frac {2 \left (a^3 \cot (c+d x)+a^3\right ) (e \cot (c+d x))^{5/2}}{7 d e} \]
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Rubi [A] time = 0.26, antiderivative size = 160, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 25, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.200, Rules used = {3566, 3630, 3528, 3532, 208} \[ -\frac {2 \sqrt {2} a^3 e^{3/2} \tanh ^{-1}\left (\frac {\sqrt {e} \cot (c+d x)+\sqrt {e}}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{d}-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {4 a^3 (e \cot (c+d x))^{3/2}}{3 d}+\frac {4 a^3 e \sqrt {e \cot (c+d x)}}{d}-\frac {2 \left (a^3 \cot (c+d x)+a^3\right ) (e \cot (c+d x))^{5/2}}{7 d e} \]
Antiderivative was successfully verified.
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Rule 208
Rule 3528
Rule 3532
Rule 3566
Rule 3630
Rubi steps
\begin {align*} \int (e \cot (c+d x))^{3/2} (a+a \cot (c+d x))^3 \, dx &=-\frac {2 (e \cot (c+d x))^{5/2} \left (a^3+a^3 \cot (c+d x)\right )}{7 d e}-\frac {2 \int (e \cot (c+d x))^{3/2} \left (-a^3 e-7 a^3 e \cot (c+d x)-8 a^3 e \cot ^2(c+d x)\right ) \, dx}{7 e}\\ &=-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {2 (e \cot (c+d x))^{5/2} \left (a^3+a^3 \cot (c+d x)\right )}{7 d e}-\frac {2 \int (e \cot (c+d x))^{3/2} \left (7 a^3 e-7 a^3 e \cot (c+d x)\right ) \, dx}{7 e}\\ &=-\frac {4 a^3 (e \cot (c+d x))^{3/2}}{3 d}-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {2 (e \cot (c+d x))^{5/2} \left (a^3+a^3 \cot (c+d x)\right )}{7 d e}-\frac {2 \int \sqrt {e \cot (c+d x)} \left (7 a^3 e^2+7 a^3 e^2 \cot (c+d x)\right ) \, dx}{7 e}\\ &=\frac {4 a^3 e \sqrt {e \cot (c+d x)}}{d}-\frac {4 a^3 (e \cot (c+d x))^{3/2}}{3 d}-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {2 (e \cot (c+d x))^{5/2} \left (a^3+a^3 \cot (c+d x)\right )}{7 d e}-\frac {2 \int \frac {-7 a^3 e^3+7 a^3 e^3 \cot (c+d x)}{\sqrt {e \cot (c+d x)}} \, dx}{7 e}\\ &=\frac {4 a^3 e \sqrt {e \cot (c+d x)}}{d}-\frac {4 a^3 (e \cot (c+d x))^{3/2}}{3 d}-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {2 (e \cot (c+d x))^{5/2} \left (a^3+a^3 \cot (c+d x)\right )}{7 d e}+\frac {\left (28 a^6 e^5\right ) \operatorname {Subst}\left (\int \frac {1}{98 a^6 e^6-e x^2} \, dx,x,\frac {-7 a^3 e^3-7 a^3 e^3 \cot (c+d x)}{\sqrt {e \cot (c+d x)}}\right )}{d}\\ &=-\frac {2 \sqrt {2} a^3 e^{3/2} \tanh ^{-1}\left (\frac {\sqrt {e}+\sqrt {e} \cot (c+d x)}{\sqrt {2} \sqrt {e \cot (c+d x)}}\right )}{d}+\frac {4 a^3 e \sqrt {e \cot (c+d x)}}{d}-\frac {4 a^3 (e \cot (c+d x))^{3/2}}{3 d}-\frac {32 a^3 (e \cot (c+d x))^{5/2}}{35 d e}-\frac {2 (e \cot (c+d x))^{5/2} \left (a^3+a^3 \cot (c+d x)\right )}{7 d e}\\ \end {align*}
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Mathematica [C] time = 2.81, size = 332, normalized size = 2.08 \[ \frac {a^3 \sin (c+d x) (\cot (c+d x)+1)^3 (e \cot (c+d x))^{3/2} \left (280 \sin ^2(c+d x) \cot ^{\frac {3}{2}}(c+d x) \, _2F_1\left (\frac {3}{4},1;\frac {7}{4};-\cot ^2(c+d x)\right )-60 \cos ^2(c+d x) \cot ^{\frac {3}{2}}(c+d x)-280 \sin ^2(c+d x) \cot ^{\frac {3}{2}}(c+d x)-126 \sin (2 (c+d x)) \cot ^{\frac {3}{2}}(c+d x)+840 \sin ^2(c+d x) \sqrt {\cot (c+d x)}+105 \sqrt {2} \sin ^2(c+d x) \log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )-105 \sqrt {2} \sin ^2(c+d x) \log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )+210 \sqrt {2} \sin ^2(c+d x) \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )-210 \sqrt {2} \sin ^2(c+d x) \tan ^{-1}\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )\right )}{210 d \cot ^{\frac {3}{2}}(c+d x) (\sin (c+d x)+\cos (c+d x))^3} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.72, size = 487, normalized size = 3.04 \[ \left [\frac {105 \, \sqrt {2} {\left (a^{3} e \cos \left (2 \, d x + 2 \, c\right ) - a^{3} e\right )} \sqrt {e} \log \left (\sqrt {2} \sqrt {e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (\cos \left (2 \, d x + 2 \, c\right ) - \sin \left (2 \, d x + 2 \, c\right ) - 1\right )} + 2 \, e \sin \left (2 \, d x + 2 \, c\right ) + e\right ) \sin \left (2 \, d x + 2 \, c\right ) - 2 \, {\left (55 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right )^{2} - 30 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right ) - 85 \, a^{3} e - 21 \, {\left (13 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right ) - 7 \, a^{3} e\right )} \sin \left (2 \, d x + 2 \, c\right )\right )} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}}{105 \, {\left (d \cos \left (2 \, d x + 2 \, c\right ) - d\right )} \sin \left (2 \, d x + 2 \, c\right )}, \frac {2 \, {\left (105 \, \sqrt {2} {\left (a^{3} e \cos \left (2 \, d x + 2 \, c\right ) - a^{3} e\right )} \sqrt {-e} \arctan \left (\frac {\sqrt {2} \sqrt {-e} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}} {\left (\cos \left (2 \, d x + 2 \, c\right ) + \sin \left (2 \, d x + 2 \, c\right ) + 1\right )}}{2 \, {\left (e \cos \left (2 \, d x + 2 \, c\right ) + e\right )}}\right ) \sin \left (2 \, d x + 2 \, c\right ) - {\left (55 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right )^{2} - 30 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right ) - 85 \, a^{3} e - 21 \, {\left (13 \, a^{3} e \cos \left (2 \, d x + 2 \, c\right ) - 7 \, a^{3} e\right )} \sin \left (2 \, d x + 2 \, c\right )\right )} \sqrt {\frac {e \cos \left (2 \, d x + 2 \, c\right ) + e}{\sin \left (2 \, d x + 2 \, c\right )}}\right )}}{105 \, {\left (d \cos \left (2 \, d x + 2 \, c\right ) - d\right )} \sin \left (2 \, d x + 2 \, c\right )}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int {\left (a \cot \left (d x + c\right ) + a\right )}^{3} \left (e \cot \left (d x + c\right )\right )^{\frac {3}{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 0.87, size = 419, normalized size = 2.62 \[ -\frac {2 a^{3} \left (e \cot \left (d x +c \right )\right )^{\frac {7}{2}}}{7 d \,e^{2}}-\frac {6 a^{3} \left (e \cot \left (d x +c \right )\right )^{\frac {5}{2}}}{5 d e}-\frac {4 a^{3} \left (e \cot \left (d x +c \right )\right )^{\frac {3}{2}}}{3 d}+\frac {4 a^{3} e \sqrt {e \cot \left (d x +c \right )}}{d}-\frac {a^{3} e \left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \ln \left (\frac {e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )}{2 d}-\frac {a^{3} e \left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{d}+\frac {a^{3} e \left (e^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{d}+\frac {a^{3} e^{2} \sqrt {2}\, \ln \left (\frac {e \cot \left (d x +c \right )-\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}{e \cot \left (d x +c \right )+\left (e^{2}\right )^{\frac {1}{4}} \sqrt {e \cot \left (d x +c \right )}\, \sqrt {2}+\sqrt {e^{2}}}\right )}{2 d \left (e^{2}\right )^{\frac {1}{4}}}+\frac {a^{3} e^{2} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{d \left (e^{2}\right )^{\frac {1}{4}}}-\frac {a^{3} e^{2} \sqrt {2}\, \arctan \left (-\frac {\sqrt {2}\, \sqrt {e \cot \left (d x +c \right )}}{\left (e^{2}\right )^{\frac {1}{4}}}+1\right )}{d \left (e^{2}\right )^{\frac {1}{4}}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.47, size = 175, normalized size = 1.09 \[ -\frac {{\left (105 \, a^{3} e {\left (\frac {\sqrt {2} \log \left (\sqrt {2} \sqrt {e} \sqrt {\frac {e}{\tan \left (d x + c\right )}} + e + \frac {e}{\tan \left (d x + c\right )}\right )}{\sqrt {e}} - \frac {\sqrt {2} \log \left (-\sqrt {2} \sqrt {e} \sqrt {\frac {e}{\tan \left (d x + c\right )}} + e + \frac {e}{\tan \left (d x + c\right )}\right )}{\sqrt {e}}\right )} - \frac {2 \, {\left (210 \, a^{3} e^{3} \sqrt {\frac {e}{\tan \left (d x + c\right )}} - 70 \, a^{3} e^{2} \left (\frac {e}{\tan \left (d x + c\right )}\right )^{\frac {3}{2}} - 63 \, a^{3} e \left (\frac {e}{\tan \left (d x + c\right )}\right )^{\frac {5}{2}} - 15 \, a^{3} \left (\frac {e}{\tan \left (d x + c\right )}\right )^{\frac {7}{2}}\right )}}{e^{3}}\right )} e}{105 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 1.62, size = 143, normalized size = 0.89 \[ \frac {4\,a^3\,e\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}}{d}-\frac {6\,a^3\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{5/2}}{5\,d\,e}-\frac {2\,a^3\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{7/2}}{7\,d\,e^2}-\frac {4\,a^3\,{\left (e\,\mathrm {cot}\left (c+d\,x\right )\right )}^{3/2}}{3\,d}+\frac {\sqrt {2}\,a^3\,e^{3/2}\,\mathrm {atan}\left (\frac {\sqrt {2}\,a^6\,e^{9/2}\,\sqrt {e\,\mathrm {cot}\left (c+d\,x\right )}\,32{}\mathrm {i}}{32\,a^6\,e^5+32\,a^6\,e^5\,\mathrm {cot}\left (c+d\,x\right )}\right )\,2{}\mathrm {i}}{d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ a^{3} \left (\int \left (e \cot {\left (c + d x \right )}\right )^{\frac {3}{2}}\, dx + \int 3 \left (e \cot {\left (c + d x \right )}\right )^{\frac {3}{2}} \cot {\left (c + d x \right )}\, dx + \int 3 \left (e \cot {\left (c + d x \right )}\right )^{\frac {3}{2}} \cot ^{2}{\left (c + d x \right )}\, dx + \int \left (e \cot {\left (c + d x \right )}\right )^{\frac {3}{2}} \cot ^{3}{\left (c + d x \right )}\, dx\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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